Speed, distance, time
Average speed, distance travelled or travel time, with the duration in hours-minutes-seconds and km/h ↔ m/s conversion.
Result
50 km/h
- Calculation
- v = 100 000 m / 7200 s = 13.889 m/s
- Pace
- 1 min 12 s / km
- Average speed
- 50 km/h · 13.889 m/s
- Distance travelled
- 100 km
- Travel time
- 2 h 0 min 0 s
Notes (2)
The average speed is 50 km/h, that is 13.889 m/s.
Average speed, stops included if they are in the duration.
Calculation, assumptions and sources
OverviewThe relation v = d / t in all three directions: average speed from distance and duration, distance from speed and duration, travel time from distance and speed.
The relation v = d / t in all three directions: average speed from distance and duration, distance from speed and duration, travel time from distance and speed. The duration is entered in hours, minutes and seconds. The speed is returned in km/h, in m/s (exact factor 3.6) and as a pace per kilometre.
Method & formulasv = d / t
The factor 3.6 between km/h and m/s is exact: 3600 seconds per hour, 1000 metres per kilometre. Pace is the inverse of speed, per kilometre: 12 km/h corresponds to 5 min/km.
- Average speed
- total distance divided by total time, stops included if they are in the duration.
- Instantaneous speed
- the one on the dial, at a given instant; the entered totals do not give it.
- Pace
- time per kilometre, the inverse of speed, usual in running.
Validity domainThe results are averages over the trip; neither constant speed nor a straight line is assumed.
The results are averages over the trip; neither constant speed nor a straight line is assumed. The travel time t = d / v assumes the speed is held on average over the whole distance; with stops, the result is a lower bound.
The average of a round tripGoing out at 60 km/h and back the same way at 40 km/h gives an average of 48 km/h, not 50.
Going out at 60 km/h and back the same way at 40 km/h gives an average of 48 km/h, not 50. The slow leg lasts longer; the time-weighted average is the harmonic mean, 2 / (1/60 + 1/40) = 48. Average speed is computed from total distance and total time.